Assignment:
Since our projectile travels at a constant rate of 340 ft / sec in the horizontal direction, we have, using the formula D = RT, that our horizontal distance x = 340 t, giving
t = x / 340
Our above equation h(t) can now be converted into h(x), as follows
h(x)=-16*(x/340)^2+340*x/340
giving
h(x)=-x^2/7225+x
What is the ordered pair which constitutes the vertex of our parabolic equation h(x)?
At what distance from our firing point does our projectile reach maximum height?
What are the ordered pairs corresponding to the zeros of the above equation h(x) (solutions to the equation -x^2/7225+x=0)?
How far does our projectile travel?
Provide complete and step by step solution for the question and show calculations and use formulas.