A rigid, sealed 1936 Ford coupe contains an equilibrium water liquid-vapor mixture with a quality of 8.8333% at 3.00 psia. After 500. Btu of heat energy are added to the coupe, the content becomes a saturated vapor. What is the total mass of water in the coupe? Fill in the following table (with correct units) and show all calculations. Unknown: m = unknown?
Helpful Hint: 1W2 = 0 (rigid vessel), T1 is found using pressure steam tables. Specific volume (v1) and internal energy (u1) are determined given the quality of the fluid-vapor mixture and the equation that relates to them. Since this is a rigid vessel, v2 = v1. State 2 is saturated vapor, the value for v2 can be used to specify p2, T2, and u2 using the pressure steam tables. Solve for m using the modified EB expression (ke and pe terms drop out).
Please show ALL work!
Process = unknown? / 1Q2 = 500 Btu
State 1
p1 = 3.00 psia
x1 = 0.088333
v1 = unknown?
T1 = unknown?
State 2
p2 = unknown?
x2 = 1.00
v2 = unknown?
T2 = unknown?
u2 = unknown?