Determine the stress intensity factor for the center


Question 1 - Determine the stress intensity factor for the edge cracked panel (consider σys = 63 (ksi)) for the following cases:

A) No plastic zone adjustment

B) With plastic zone adjustment for both √(πa) and β for plane stress

C) With plastic zone adjustment for both √(πa) and β for plane strain

877_Figure1.png

Question 2 - Determine the stress intensity factor for the center cracked panel (consider σys = 63 (ksi)) for the following cases:

A) No plastic zone adjustment

B) Plain Strain: plastic zone adjustment only to √(πa)

C) Plane Stress: plastic zone adjustment only to √(πa)

D) Plain Strain: plastic zone adjustment for both √(πa) and β

E) Plain Stress: plastic zone adjustment for both √(πa) and β

468_Figure2.png

Question 3 - Determine the stress intensity factor for the center cracked panel (consider σys = 63 (ksi)) for the following cases:

A) σ = 15 (ksi) in Plane Stress

1- No plastic zone adjustment

2- With plastic zone adjustment for only √(πa)

3- With plastic zone adjustment for both √(πa) and β

B) σ = 30 (ksi) in Plane Stress

4- No plastic zone adjustment

5- With plastic zone adjustment for only √(πa)

6- With plastic zone adjustment for both √(πa) and β

1666_Figure3.png

Question 4 - Plot the plastic zone shape rp vs. θ, according to the Von Mises yield criterion for the edge cracked panel. Use σys = 50 (ksi)

A) Plane Stress

B) Plane Strain

673_Figure4.png

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Mechanical Engineering: Determine the stress intensity factor for the center
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