Determine the molar gibbs function of pure water


Solve the following problem:

A very small amount of sugar is dissolved in water, and the solution is in equilibrium with pure ice. The equation of phase equilibrium is

g’ = g’’ + RT In (1 - x),

Where g’ is the molar Gibbs function of pure ice, s" is the molar Gibbs function of pure water, and x is the mole fraction of sugar in solution.

(a) For an infinitesimal change in x at constant pressure, show that

-s’ dT = -s’’ dT + R In (1-x) dT + RTd In (1-x).

(b) Substituting for R In (1 - x) the value obtained from the equation of phase equilibrium, show that the equation in part (a) reduces to

(h’’ - h’/T)dT = RT d In (1 - x)

(c) Taking into account that x « 1 and calling h" - h’ the latent heat of fusion IF, show that the depression of the freezing point is

ΔT = (RT2/ IF)x .

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Chemistry: Determine the molar gibbs function of pure water
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