Determine temperature in c specific enthalpy in kj-kg
Propane undergoes a process from state 1 where p1=1.4 MPa T1=60 C to state 2 where p2=1.0 MPa during which the change in specific entropy is s2-s1=-0.035 kJ/Kg*K At state 2 determine the temperature in C the specific enthalpy in kJ/Kg.
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Propane undergoes a process from state 1 where p1=1.4 MPa T1=60 C to state 2 where p2=1.0 MPa during which the change in specific entropy is s2-s1=-0.035 kJ/Kg*K.
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