Under some conditions maximum height y attained by the basketball released from the height h at the angle measured from horizontal with the initial velocity v0 is given by
y = h + v0^2(sin(angle)^2/(2g), where g is acceleration due to gravity. Determine maximum height reached by the free throw if h = 1.89 m, v0 = 7 m/s, angle= 64.47°, and g = 9.81 m/s2.