Determine heat rejection rate to surrounding-cooling rate


R-134a enters the condenser of a refrigerator at 800kPa and 50oC at a rate of 0.018kg/s and leaves at 800kPa as a saturated liquid. It is known that the compressor consumes 1.2kW of electricity at this operating condition. Determine 1) heat rejection rate to the surrounding; 2) cooling rate; and 3) the COP of the refrigerator?

Request for Solution File

Ask an Expert for Answer!!
Mechanical Engineering: Determine heat rejection rate to surrounding-cooling rate
Reference No:- TGS0739610

Expected delivery within 24 Hours