Construct a 90 confidence interval for the mean age of all


How do you find confidence interval and the t* in Margin of Error

e.g

A survey of 25 randomly selected customers found the ages shown? (in years). The mean is 32.00 years and the standard deviation is 9.44years.

?a) Construct a 90?% confidence interval for the mean age of all? customers, assuming that the assumptions and conditions for the confidence interval have been met.

?b) How large is the margin of? error?

?c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?

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Business Management: Construct a 90 confidence interval for the mean age of all
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