Computing magnitude of the acceleration due to gravity
What must the charge (sign and magnitude) of a particle of mass 1.47 be for it to remain stationary when placed in a downward-directed electric field of magnitude 610 ?
Use 9.81 for the magnitude of the acceleration due to gravity.
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For a spherical celestial object of radius R, the acceleration due to gravity g at a distance x from the center of the object is g = g0R2/x2, where g0 is the acceleration due to gravity at the object's surface and x > R.
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What must the charge (sign and magnitude) of a particle of mass 1.47 be for it to remain stationary when placed in a downward-directed electric field of magnitude 610? Use 9.81 for the magnitude of the acceleration due to gravity.
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