y'=y+1 , y(0)=1 ; y(x)= 2e^(x) -1 An Initial value problem and its exact solutions y(x) are given . Apply euler's method twice to aproximate to this solution on the interval [0,(1/2)] , first we step size h=0.25 then we step size h=0.1 . Compare the three-decimal-place values of the two approximations at x=(1/2) with the value y(1/2) of the actual solution . then do the same for PART B: y'=-2xy , y(0)=2 ; y(x)=2e^(-x^2)