Change in the electric potential energy of the particle


A uniform electric field has a magnitude 1.90 kV/m and points in the +x direction.

(a) What is the electric potential difference between x = 0.00 m plane and the x = 4.10 m plane?

(b) A point particle that has a charge of +2.90 µC is released from rest at the origin. What is the change in the electric potential energy of the particle as it travels from the x = 0.00 m plane to the x = 4.10 m plane?

(c) What is the kinetic energy of the particle when it arrives at the x = 4.10 m plane?

(d) Find the expression for the electric potential V(x) if its value is chosen to be zero at x = 0.

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Physics: Change in the electric potential energy of the particle
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