Calculate weight percent of Fe in ore with .4919g of sample with 11ml of .25M Sn2Cl (56.5010g) and 10mL of .25M Hg2Cl (67.8644g) as analyte titrating 1.0058g of potassium dichromate diluting with water with initial weight of 240.26g of potassium dichromate and final weight of 208.71g with change weight of 31.55g. And
Equation 1: Fe2O3+6H------->2Fe +3H2O
Equation 2: xs. Sn (II) + 2Fe (yellow) --->Sn (IV) +2 Fe (light green)
Equation 3: Sn (II) +2Hg (from HgCl2) +2Cl ----->Hg2Cl2(s) +Sn (IV)
Equation 4: xs. Sn (II) +hg ---> Hg (s) +Sn (IV)
Equation 5: Cr2O7 +6Fe+14H --->2Cr +6Fe+7H2O