Calculate the theoretical yield of the resulting alum
A mass of 12.96 gram of (NH4)2SO4(molar mass= 132.06g/mol) is dissolved in water. After the solutionis heated, 25.11grams of Al2(SO4)3 18H2O (molar mass = 666.36 g/mol) is added. Calculate the theoretical yield of the resulting alum.
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A mass of 12.96 gram of (NH4)2SO4(molar mass= 132.06g/mol) is dissolved in water. After the solutionis heated, 25.11grams of Al2(SO4)3 18H2O (molar mass = 666.36 g/mol) is added.
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18H2O (molar mass = 666.36 g/mol) is added. Calculate the theoretical yield of the resulting alum.