2.253 grams of the drug candidate was ignited and 6.035 g of carbon dioxide and 1.481 g of water vapor were detected. A combustion analysis was attempted to elucidate the molecular formula of this substance.
1. Calculate the empirical formula of the drug candidate.
2. Calculate the molecular formula of the drug candidate.
3. Determine the "correct" molar mass of the compound.
4. Based on the "correct" molar mass, calculate the % error.
Percent error = Theoretical value - Actual value/ Actual value x 100
5. Determine the % yield of carbon dioxide in the combustion analysis.