Calculate the molality m of the following solutions a650 g
calculate the molality (m) of the following solutions: a)65.0 g of glucose, C6H12)6, a nonelectrolyte, added to .112 kg of water. b).320 mol of sucrose, C12H22O11, a nonelectrolyte, dissolved in 1.50 kg of water?
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Starting from the appropriate Maxwell's equation determine the relationship between tangential components of the electric fields on either side of a boundary separating two dielectric meddia with dielectric permittivity e1 and e2 .
A current of 6.80 A is located at the origin. (This current flows parallel to the z axis, with a positive current flowing in the + k direction.) Find the magnetic field at a point 6.27 cm along the -x axis,
how many moles of each of the following strong electrolytes are needed to give the same freezing point lowering as 3.0 mol of the nonelectrolyte ethylene glycol in 1 kg of water? a)CH3-OH, a nonelectrolyte. b)KNO3
A parallel plate vacuum capacitor is connected to a battery and charged until the stored electric energy is u, Find u, the energy dissipated in the resistor
calculate the molality (m) of the following solutions: a)65.0 g of glucose, C6H12)6, a nonelectrolyte, added to .112 kg of water. b).320 mol of sucrose, C12H22O11, a nonelectrolyte, dissolved in 1.50 kg of water
The nucleus of 8Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particles, What is the force between the two alpha particles when they are 5.20 10-15 m apart
A single phase two winding transformer having rating: 20 KVA,480/120 V, 60 Hz A source connected to the 480 V winding supplies an impedance load connected to 120 V winding. The load absorbs 15 KVA at 0.8 pf lagging when load voltage is118 V.
The electric field everywhere on the surface of a charged sphere of radius 0.180 m has a magnitude of 500 N/C, What is the net charge on the sphere
at a particular temperature, N2O5 decomposes according to a first-order rate law with a half-life of 3.0s. If the initial concentration of N2O5 is 1.0x10^-6 molecules/cm^3, what will be the concentration in molecules/cm^3 after 26.1s
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