Calculate the angle for the third-order maximum of 595 nm, Physics

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Calculate the angle for the third-order maximum of 595 nm

Calculate the angle for the third-order maximum of 595 nm wavelength yellow light falling on double slits separated by 0.125 mm.

I understand the formula to be 1.25x10^-4(sin(angle) = 3(595x10^-9) and I get sin (angle) = .01428 but I don't know how to get the angle using sin. please spell it out entirely so I can learn the process and how to figure it out on my calc. Thanks so much in advance!!

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Physics: Calculate the angle for the third-order maximum of 595 nm

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Physics: Calculate the angle for the third-order maximum of 595 nm

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