At a certain instant a particle of charge q26mc is


Compute the all parts of given question:

Question: A wire has a current to the left as shown. At a certain instant, a particle of charge q=26mC is traveling with a velocity of 200m/s to the left. 1 mC=1 x 10-6.

Question I: If the current of the wire is 25 A, and the charge is .04 m from the wire, what is the magnetic field at the location of charge?

Question II: What is the magnitude and direction of the magnitude force on the charge?

Please use great detail in explaining the solution of above question. Thanks.

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Physics: At a certain instant a particle of charge q26mc is
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