Carry out eulers method twice to approximate to this solution on interval [0, 0.5], first with step size h = 0.25, then with step size h = 0.1. Compare the three decimal-place values of the two approximations at x = 0.5 with the value y(0.5) of the actual solution. Solve for the following: 1) y' = y - x - 1, y(0) = 1; y(x) = 2 + x - e^x 2) y' = -2xy, y(0) =2; y(x) = 2(e^(-x^2))