An electron has a kinetic energy of 47 x 10-17 j determine, Physics

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An electron has a kinetic energy of 47 x 10-17 j determine

Solve the following problem given below:

Problem: An electron has a kinetic energy of 4.7 x 10^-17 J. It moves on a circular path that is perpendicular to a uniform magnetic field of magnitude 5.1 x 10^-5 T.

Part A- Determine the radius of the path.

Rework your solution from the beginning and check each step carefully.

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Physics: An electron has a kinetic energy of 47 x 10-17 j determine

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Physics: An electron has a kinetic energy of 47 x 10-17 j determine

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