An amusement park ride is engineered to toss a victim


Question: An amusement park ride is engineered to toss a victim straight up at 30 mph and then to have this victim fall into a pool of water 20 ft below the starting position. To estimate the likelihood that the victim will throw up, the time that the victim will be airborne is needed.

Part A: What is this time?

Please do a step by step solution since I'm kind of lost with this question.

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Physics: An amusement park ride is engineered to toss a victim
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