Adjacent antinodes of a standing wave on a string are 160


Solve the all parts of following problem given below:

Problem: Adjacent antinodes of a standing wave on a string are 16.0 cm apart. A particle at antinodes oscillates in simple harmonic motion with amplitude 0.845 cm and period 0.0800 s. The string lies along the x-axis and is fixed at x = 0.

Part I: How far apart are the adjacent nodes?

cm

Part II: What are the wavelength, amplitude, and speed of the two traveling waves that form this pattern?

wavelength cm

amplitude cm

speed m/s

Part III: Find the maximum and minimum transverse speeds of a point at an antinodes.

vmax = m/s

vmin = m/s

Part IV: What is the shortest distance along the string between node and antinodes?

cm

Show all work, use additional paper if necessary.

Request for Solution File

Ask an Expert for Answer!!
Physics: Adjacent antinodes of a standing wave on a string are 160
Reference No:- TGS0945181

Expected delivery within 24 Hours