A student synthesized 6.895 g of barium iodate monohydrate, Ba(IO3)2.H20 by adding 30.00 ml of 5.912x10^-1 M barium nitrate Ba(NO3)2 to 50.00ml of 9.004 x10^-1 M sodium iodate,NaIO3.
What is the percent yield of barium iodate monohydrate obtained in the experiment