A proton m0c2 938mev bends with a radius of curvature of


Question: A proton, (M0c2 = 938MeV) bends with a radius of curvature of 1m in a magnetic field of 0.1T. What are the momentum and the kinetic energy of that proton?

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Physics: A proton m0c2 938mev bends with a radius of curvature of
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