A photoelectric surface has a work function of 4ev what is
A photoelectric surface has a work function of 4eV. What is the maximum velocity of the photoelectrons emitted by light if frequency 10^15 Hz incident on the surface?
h = 6.6 * 10^-34 Joules-second
e = 1.6 * 10^-19 Coulomb
m = 9 * 10^-31 kg
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A photoelectric surface has a work function of 4eV. What is the maximum velocity of the photoelectrons emitted by light if frequency 10^15 Hz incident on the surface h = 6.6 * 10^-34 Joules-second e = 1.6 * 10^-19 Coulomb
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