A pebble is thrown vertically upward at a speed of 2990 ms


A pebble is thrown vertically upward at a speed of 29.90 m/s at time t=0. A second pebble is thrown upward with the similar speed 2.070 sec later.

Determine at what time are the two pebbles at the same height?

Determine at what height do the two pebbles pass each other?

Determine the downward speed of the first pebble as they pass each other?

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Physics: A pebble is thrown vertically upward at a speed of 2990 ms
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