A particle has a charge of +1.5µC and moves from point C to point D, a distance of 0.19 meter. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at C and D is EPEC - EPED = +6.00 x 10-4 Joule.
a) Determine the direction and magnitude of the electric force that acts on the particle.
b) Determine the direction and magnitude of the electric field that the particle experiences.