A particle executes linear some with an amplitude if 2 cm.when the particle is at 1cm from the mean position the magnitude of its velocity is equal to that of its acceleration.Then its time period is?
Ans) velocity at distance x in shm is given as
v= w sqrt(A2-x2)
so A = 2 x =1
v = w sqrt(4-1) = wsqrt3
now acc at distance x is a= w2 x = w2
as mag a = mag v
w2 = wsqrt3
w= sqrt3
2pi/T= sqrt3
T = 2pi/sqrt3