A long rod of lenght " L " and cross sectional area "A" is weighted such that when it is placed in a bucket of water it floats vertically. At equilibrium the depth of the 'heavy' end of the rod is " L/2 " .
a) Draw a free body diagram for the rod. If L=0.15 m , and A=10^-4 cm^2 , determine the magnitude of the buoyant force on the rod (take Pwater = 1 g/cm^3 ). If the acceleration due to gravity is 10 m/s^2 , what is the mass of the rod ?
b) Suppose the rod is pushed deeper into the water by some amount " \delta x " from the water. Draw a third free body diagram and find the sum of the buoyant and weight forces acting on the rod.