A hydrogen atom has an ionization energy of 136 ev an
A hydrogen atom has an ionization energy of 13.6 ev. An electron in the n = 4 state makes a transition to the n = 2 state. What is the wavelength of the emitted photon? (hc = 1234 ev*nm) A) 366 nm B) 1460 nm C) 487 nm D) 635 nm E) 260 nm
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a hydrogen atom has an ionization energy of 136 ev an electron in the n 4 state makes a transition to the n 2 state
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