A dynamite blast at a quarry launches a rock straight


Solve the all parts of given problem:

Problem: A dynamite blast at a quarry launches a rock straight upward, and 1.7 s later it is rising at a rate of 14 m/s. Assuming air resistance has no effect on the rock,

Part A: Calculate its speed at launch?

Part B: Calculate its speed at 4.3 s after launch?

Please show your all work and steps I am really confused.

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Physics: A dynamite blast at a quarry launches a rock straight
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