A current it 10rt ma is applied to a 10 mf capacitor for t


1.A voltage is described as v(t) = 3u(t) - 3u(t-3) V where u(t) is the step function. The values at t = 2 seconds and t = 4 seconds are x and y respectively, where:

A) x = 3 V and y = -3 V.

B) x = 0 V and y = 3 V.

C) x = 3 V and y = 0 V.

2. A current is described by the function i(t) = 5cos(1000t - 2) mA. The argument of the cosine is in radians and t is in seconds. The frequency may be expressed as:

A) 2 radians/s

B) 1000 Hz

C) 159 Hz

D) 159 radians/s

E) 2 Hz

F) 6280 Hz

3. Consider the signal v(t) = 10cos3000t + 10sin3000t. The peak-to-peak value is:

A) 28.28 V

B) 14.14 V

C) 10 V

D) 20 V

4. A current i(t) = 10r(t) mA is applied to a 10 mF capacitor for t > 0, where r(t) is the ramp function. At t= 0, the capacitor voltage was zero. The voltage across the capacitor at t = 2 s is:

A) 2.0 V

B) 0.5 V

C) 2.5 V

D) 1.5 V

E) 1.0 V

5. The voltage applied to a 100 mF capacitor is v(t) = 10r(t) V. The current through the capacitor at t = 2 s is:

A) 1.0 V

B) 2.0 V

C) 500 mV

D) 5.0 V

E) 200 mV

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Electrical Engineering: A current it 10rt ma is applied to a 10 mf capacitor for t
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