A charge q1 110 x 10-9 c is a distance r 400 cm away from


Solve the all parts of given question:

Question: A charge Q1 = 1.10 x 10-9 C is a distance r = 4.00 cm away from a charge Q2 = -8.25 x 10-9 C.

Part A: Calculate the magnitude of the force on Q1 due to Q2.

Part B: Calculate the potential at a location 2.56 cm from Q1 and 1.59 cm from Q2.

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Physics: A charge q1 110 x 10-9 c is a distance r 400 cm away from
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