A cannon located 680 m from the base of a vertical 260-m


Compute all parts of given question:

Question: A cannon, located 68.0 m from the base of a vertical 26.0-m tall cliff, shoots a 16-kg shell at 43.0° above the horizontal toward the cliff.

Part A: What must the minimum muzzle velocity be for the shell to clear the top of the cliff?

Part B: The ground at the top of the cliff is level, with a constant elevation of 26.0 m above the cannon. Under the conditions of part (a), how far does the shell land past the edge of the cliff?

I need help to find the minimum muzzle velocity be for the shell to clear the top of the cliff.

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Physics: A cannon located 680 m from the base of a vertical 260-m
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