Solve the each part of given question:
Question: A blue ball is thrown upward with an initial speed of 20.4 m/s, from a height of 0.6 meters above the ground. 2.5 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 10.9 m/s from a height of 23.7 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.
Part A: What is the speed of the blue ball when it reaches its maximum height?
Part B: How long does it take the blue ball to reach its maximum height?
Part C: What is the maximum height the blue ball reaches?
Part D: What is the height of the red ball 3.25 seconds after the blue ball is thrown?
Part E: How long after the blue ball is thrown are the two balls in the air at the same height?
I am not able to get the correct answer please help me.