A ball is dropped from a height .If it takes0.200 second to cross the last 6.00 m before hitting the ground ,find the height from which it was dropped .
Ans) We need to find H
Using second eqn of motion:
6=0.2u-5(0.04).............................u is velocity at h=6m
u=31m/s
Conserving energy:
mgh=0.5m(31)2.......................................Datum line for P.E is at 6 m from ground. h= H-6
=>h=48.05m
=>H=54.05m.