A 52-kg mountain climber, starting from rest climbs a vertical distance of 730m. At the top, she is again at rest. In the process, her body generates 4.1*10^6J of energy via metabolic processes. In fact, her body acts like a heat engine, the efficiency of which is given by Eqn 15.11 as e=[W]/[QH], where [W] is the magnitude of the work she does and [QH] is the magnitude of the input heat. Find her efficiency as a heat engine.