A 12 kg particle moves from an initial position r1 4i - 2j


A 1.2 kg particle moves from an initial position r1 = 4i - 2j + 3k m to a final position r2 = 7i - 3j -4k m while a force F = 6i - 4j + 2k N acts on it. What is the work done by the force on the particle?

in joules

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Physics: A 12 kg particle moves from an initial position r1 4i - 2j
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