A 05220 g sample of an unknown monoprotic acid was titrated


A 0.5220 g sample of an unknown monoprotic acid was titrated with 9.98×10?2 M NaOH . The equivalence point of the titration occurs at 23.70 mL. Determine the molar mass of the unknown acid.

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Chemistry: A 05220 g sample of an unknown monoprotic acid was titrated
Reference No:- TGS0564419

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