A 050-kg mass attached to the end of a string swings in a


The answer to the following question is 16 N. That being F = v2/r. Why would I not also substitute mg into the equation (which would give me 11 N). Does this have to do with it being horizontal?

A 0.50-kg mass attached to the end of a string swings in a vertical circle (radius = 2.0 m). When the string is horizontal, the speed of the mass is 8.0 m/s. What is the magnitude of the force of the string on the mass at this position?

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Physics: A 050-kg mass attached to the end of a string swings in a
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