A 01669-g sample of an unknown monoprotic acid was


A 0.1669-g sample of an unknown monoprotic acid was dissolved in 33.4 mL of water and titrated with 0.0688 M NaOH solution. The volume of base required to bring the solution to the equivalence point was 16.5 mL.

(a) Calculate the molar mass of the acid.

(b) After 10.3 mL of base had been added during the titration, the pH was determined to be 5.16. What is the Ka of the unknown acid?

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Chemistry: A 01669-g sample of an unknown monoprotic acid was
Reference No:- TGS0801069

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