2al 6hbr 2albr3 3h2 if 427 g of al reacts calculate the
2Al + 6HBr = 2AlBr3 + 3H2 If .427 g of Al reacts calculate the amount of hydrogen produced
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2al 6hbr 2albr3 3h2 if 427 g of al reacts calculate the amount of hydrogen
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