Problem on making solutions
The weight of pure NaOH needed to made 250cm3 of 0.1 N solution is: (a) 4g (b) 1g (c) 2g (d) 10g Choose the right answer from above.
The weight of pure NaOH needed to made 250cm3 of 0.1 N solution is: (a) 4g (b) 1g (c) 2g (d) 10g
Choose the right answer from above.
6. 20 gm of hydrogen is present in 5 litre vessel. The molar concentration of hydrogen is
What is the normal amount of glucose in 100ml of blood (8–12 hrs after meal) is: (i) 8mg (ii) 80mg (iii) 200mg (iv) 800mg Choose the right answer from above.
Choose the right answer from following. A molal solution is one that contains one mole of a solute in: (a) 1000 gm of the solvent (b) One litre of the solvent (c) One litre of the solution (d) 22.4 litres of the solution
The diazonium salts are represented by the general formula ArN2 +X where X- ion may be anion such as (Cl) ¨, B ¨r, HSO
what is the molarity of the solution prepared by dissolving 75.5 g of pure KOH in 540 ml of solution
Help me to go through this problem. On dissolving 1 mole of each of the following acids in 1 litre water, the acid which does not give a solution of strength 1N is: (a) HCl (b) Perchloric acid (c) HNO3 (d) Phosphoric acid
Choose the right answer from following. If P and P are the vapour pressure of a solvent and its solution respectively N1 and N2 and are the mole fractions of the solvent and solute respectively, then correct relation is: (a) P= PoN1 (b) P= Po N2 (c)P0= N2 (d)
Molecular orbitals and molecular motions belong to certain symmetry species of the point group of the molecule.Examples of the special ways in which vectors or functions can be affected by symmetry operations are illustrated here. All wave functions soluti
The solubility of a gas in water depends on: (a) Nature of the gas (b) Temperature (c) Pressure of the gas (d) All of the above. Can someone help me in finding out the right answer.
20 g of hydrogen is present in 5 litre of vessel. Determine he molar concentration of hydrogen: (a) 4 (b) 1 (c) 3 (d) 2 Choose the right answer from above.
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