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Neutralization of sodium hydroxide

How much of NaOH is needed to neutralise 1500 cm3 of 0.1N HCl (given = At. wt. of Na =23): (i) 4 g  (ii) 6 g (iii) 40 g  (iv) 60 g

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The answer is (ii)

1500cm3 of .01 N HCL have number of gm equivalence

= N1 x V1/ 1000 = 1500x0.1/ 1000 = 0.15

0.15 gm. Equivalent of NaOH = 0.15 x 40 = 6 gm

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