The freezing point of equi-molal aqueous solution will be maximum for:
(a) C6H5NH3+Cl-(aniline hydrochloride) (b) Ca(NO3)2 (c) La(NO3)3 (d) C6H12O6(glucose)
Answer: (c) La(NO3)3 will furnish four ions and thus will develop more lowering in freezing point whereas glucose gives only one particle and thus minimum lowering in freezing point.