--%>

Define Bond Energies - Bond Charges

Energy changes in some chemical reactions can be used to deduce the energies of chemical bonds.


Our understanding of the molecular basis of thermodynamic properties is extended when we ask why the enthalpy change for a reaction is what it is. We deduce, for example, from the data, the value of -802.34 kJ for ΔH°298 for the reaction:

2145_bond energy.png 
 
Why it is the enthalpy change has this value?

Two relatively small contributions to the ?H term can be recognized. One contribution comes from the difference in the normal products of the thermal energies of the molecules of the products and the reactants. Another small contribution due to the volume comes from the change in number of moles of reagents.

These minor complicating contributions can be avoided by using ?H00 = ?UC values such as those o f appendix table to calculate the ?U00 value of - 804.2 kJ for the methane combination reaction. Now we ask about the molecular basis of this energy difference.

To answer such question, we adopt a traditional chemical idea. We think of the energies of many substances in terms of the chemical bonds that we imagine to be holding the atoms together. The energy of one substance compared to that of another substance is said to be due primarily to the energy "strength" of the chemical bonds.

Standard enthalpies of atomic species: we need to justify the energy data for the free gaseous atoms to calculate the energy change when the molecules of a substance are broken up into free atoms.

Enthalpy and energy data can be taken for gaseous atomic substances. These data come, usually, from spectroscopic rather from calorimetric measurements. For diametric molecules, spectral studies show the energy for breakup of these molecules into atoms. Results from the original molecules and the atoms produced, all in their lowest energy, or ground states, can be deduced from the spectral data. Thus we arrive directly at data for ?H°f,0. these energy data for atomic species can be extended to give enthalpy values, as illustrated by some of the entries in bond energies.

Bond energies: with the data begin by considering reactions that are easily given a bond energy interpretation. For example, the ΔH° ƒ, 0 can be used to obtain:

199_bond energy1.png

   Related Questions in Chemistry

  • Q : Homework Silicon has three naturally

    Silicon has three naturally occurring isotopes. 28Si, mass = 27.976927; 29Si, mass = 28.976495; 30Si, mass = 29.973770 and 3.10% abundance. What is the abundance of 28Si?

  • Q : Molarity of solution Help me to go

    Help me to go through this problem. When 7.1gm Na2SO4 (molecular mass 142) dissolves in 100ml H2O , the molarity of the solution is: (a) 2.0 M (b) 1.0 M (c) 0.5 M (d) 0.05 M

  • Q : HCl is an acid or a base Illustrate is

    Illustrate is HCl an acid or a base ?

  • Q : Concentration of Barium chloride Give

    Give me answer of this question. If 5.0gm of BaCl2 is present in 106 gm solution, the concentration is: (a)1 ppm (b)5 ppm (c)50 ppm (d)1000 ppm

  • Q : Explain the process of coagulation of

    Presence of small concentrations of appropriate electrolyte is necessary to stabilize the colloidal solutions. However, if the electrolytes are present in higher concentration, then the ions of the electrolyte neutralize the charge on the colloidal particles may unite

  • Q : Problem on mol fraction of naphthalene

    At 20°C the solubility of solid naphthalene in hexane is 0.09 mol/mol of solution. Use this information and the data below to estimate the following for this system: a) The mol fraction of naphthalene in the vapour phase in equ

  • Q : Problem on solutions The 2N aqueous

    The 2N aqueous solution of H2S04 contains: (a) 49 gm of H2S04 per litre of solution (b) 4.9 gm of H2S04 per litre of solution (c) 98 gm of H2S04

  • Q : Moles of HCl present in .70 L of a .33

    Detail the moles of HCl which are present in .70 L of a .33 M HCl solution?

  • Q : Various cons of eating the organic foods

    Describe the various cons of eating the organic foods? Briefly illustrate it.

  • Q : Raoults law Give me answer of this

    Give me answer of this question. Provide solution of this question. Which one of the following is the expression of Raoult's law: (a) P-P1/P = n/n+N (b) P1-P/P = N/ N+n (c)P-P2/P1= N/ N-n (d) P1-P/P2= N-n/N