Dipole moment of chloro-octane
Describe the dipole moment of chloro-octane in brief?
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There are manifold forms of the molecule ‘chloro-octane’. This is as the chlorine atom can be joined to the octane chain in many different places, and each and every distinct placement will outcome in a different dipole moment.
The constant of vander Waal's equation can be related to the coefficients of the virial equation. Vander Waal's equation provides a good overall description of the real gas PVT behaviour. Now let us
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On passing H2S gas through a particular solution of Cu+ and Zn+2 ions, first CuS is precipitated because : (a)Solubility product of CuS is equal to the ionic product of ZnS (b) Solubility product of CuS is equal to the solubility product
How can you decide if there is a dipole moment or not?
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Silicon has three naturally occurring isotopes. 28Si, mass = 27.976927; 29Si, mass = 28.976495; 30Si, mass = 29.973770 and 3.10% abundance. What is the abundance of 28Si?
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