In the individual transistor inverter circuit demonstrated below, the input voltage is switched abruptly by Vcc to 0V. There base current as acquired from the Charge Control equations governing turn-off of the transistor is specified as:
IB = (τF/τBF) iC + (τF/τBF) CBCRC (dic/dt) + τF(dic/dt) + CBCRC(dic/dt) = - VBE ON/RB
Determine this equation to acquire an expression for the collector current and the output voltage of the inverter throughout turn-off of the transistor. Therefore evaluate the 10 to 90 percent rise-time of the output voltage of the inverter when τF = 0.2ns, βF = 50, RC = 1kΩ, RB = 10kΩ and CBC = 0.5pF as well as VCC = 5V.
