When cs2g 6437 mol and 5191 grams of h2g in a 1900 l


When CS2(g) (6.437 mol) and 51.91 grams of H2(g) in a 190.0 L reaction vessel at 983.0 K are allowed to come to equilibrium the mixture contains 1.444 mol of CH4(g). What concentration (mol/L) of CS2(g) reacted? CS2(g)+4H2(g) = CH4(g)+2H2S(g)

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Chemistry: When cs2g 6437 mol and 5191 grams of h2g in a 1900 l
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