Weight of the spherical mass at the location


Assume that the earth is a uniform density spherical mass. (This assumption is not correct but we will use it for simplicity in working the problem.) Suppose that a hole is drilled straight toward the center of the earth to a depth of 30 000 ft. and a small 100 kg spherical mass is dropped into the hole and ends up at the very bottom of it. What would be the weight of the spherical mass at that location? Give your answer in the form "a.bc x 10^(y)" N.

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Physics: Weight of the spherical mass at the location
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