Matching of the velocity of the particle


Two particles move along an x axis. The position of particle 1 is given by x = 5.60t2 + 3.00t + 2.00 (in meters and seconds); the acceleration of particle 2 is given by a = -8.00t (in meters per seconds squared and seconds) and, at t = 0, its velocity is 19 m/s. When the velocities of the particles match, what is their velocity?

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Physics: Matching of the velocity of the particle
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